Improper integration change of variables

[Gregg]

Homework Statement

show

\int _1^{\infty }\frac{1}{x^2}\text{Log}[x]dx=-\int_0^1 \text{Log}[x] \, dx

similarly show

\int _0^{\infty }\frac{1}{x^2+1}\text{Log}[x]dx = 0

The Attempt at a Solution

For the first part a substitution 1/x works.

The second part I cannot do, I thought about

\int _0^{\infty }\frac{1}{x^2+1}\text{Log}[x]dx=\int _1^{\infty }\frac{1}{x^2+1}\text{Log}[x]dx+\int _0^1\frac{1}{x^2+1}\text{Log}[x]dx

and then trying to maybe show

\int _1^{\infty }\frac{1}{x^2+1}\text{Log}[x]dx=-\int _0^1\frac{1}{x^2+1}\text{Log}[x]dx

but for now I am not sure what to do.

 

[Dick]

Try substituting u=1/x in one of your final two integrals.

 

[Gregg]

\int _1^{\infty }\frac{1}{x^2+1}\text{Log}[x]dx=\int _1^0\frac{1}{u^2+1}\text{Log}<u>du </u>

\int _1^{\infty }\frac{1}{x^2+1}\text{Log}[x]dx+\int _0^1\frac{1}{x^2+1}\text{Log}[x]dx=\int _0^{\infty }\frac{1}{x^2+1}\text{Log}[x]dx=0

thanks!