Impulse momentum theory, a ball strikes a wall dunno if i got it right?

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Homework Help Overview

The discussion revolves around a physics problem involving impulse and momentum, specifically analyzing the force exerted by a wall on a ball during a collision. The ball has a mass of 0.15 kg and initial and final velocities of 5 m/s and 3 m/s, respectively, with a contact time of 0.1 seconds.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the calculation of force using the impulse-momentum theorem and question the implications of negative values in their results. There is discussion about the directionality of velocity and how it affects the sign of the force.

Discussion Status

Participants are actively engaging with the problem, questioning their assumptions about velocity direction and the resulting force calculations. Some have proposed different interpretations of the signs in their calculations, leading to varying conclusions about the force's direction.

Contextual Notes

There is an ongoing discussion about the choice of positive and negative directions for velocity, which impacts the calculations. Participants are considering how these choices affect their understanding of the force exerted during the collision.

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Homework Statement


a ball w/ mass of .15kg and a velocity of 5m/s strikes a wall and bounces right back with v=3m/s. ball is in contact with wall for 0.1 sec, how much force did the wall exert on the ball?


Homework Equations


Ft=mvf-mvi
F=?
t=0.1
m=.15
vf=3m/s
vi=5

The Attempt at a Solution



0.1F=(.15*3)-(.15*5)
0.1F= -.30
F= -3 N

How could the force be negative?? did i do something wrong?
 
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Velocity and momentum are vectors, which means you have to take into account the direction of the velocities (plus or minus) before and after the collision. Your answer is not correct. If the force is negative, what does that imply?
 
PhanthomJay said:
Velocity and momentum are vectors, which means you have to take into account the direction of the velocities (plus or minus) before and after the collision. Your answer is not correct. If the force is negative, what does that imply?

OOOH okayy i don't know how i forgot that!
i just don't know which one is negative. i made the inital velocity negative, and i got 12N for the answer...is that right?

i got:
0.1F=(.15*3)+(.15*5)
F=12

when i made the final velocity negative i got 3N

im so confused
 
12 N for the average force is correct, but what is the direction of the 12 N force? You can choose any direction as negative, as long as you choose the opposite direction as positive. If you make the final velocity negative, then the initial velocity is positive. In which case,
0.1F = .15*(-3) - (.15*5)
F = - 12 N
How do you interpret the minus sign??
 
PhanthomJay said:
12 N for the average force is correct, but what is the direction of the 12 N force? You can choose any direction as negative, as long as you choose the opposite direction as positive. If you make the final velocity negative, then the initial velocity is positive. In which case,
0.1F = .15*(-3) - (.15*5)
F = - 12 N
How do you interpret the minus sign??
um...12N toward the wall?
 
The ball exerts an average 12 N force on and pointing toward the wall, so the wall must exert an average 12 N force on the ball in the direction, per Newton 3, pointing away from? or toward? the wall. The sign of the force corresponds to the signs you chose for the direction of the velocities.
 

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