Acceleration on Inclined Plane and Pulley System

AI Thread Summary
The discussion revolves around calculating the acceleration of mass m2 on an inclined plane in a pulley system involving two masses, m1 and m2, with given values and coefficients of friction. The user initially derived equations based on free body diagrams but later questioned the correctness of their results, which indicated negative acceleration for m2, suggesting a direction opposite to their assumption. They calculated tensions and accelerations for both masses, arriving at different values in two attempts. Suggestions were made to simplify the system and consider the mechanical advantage provided by the pulley. The user is seeking verification of their calculations and understanding of the system dynamics.
aaronfue
Messages
118
Reaction score
0

Homework Statement



I believe that I have my answer. I would appreciate it if someone could check my work.

m1 = 33 kg
m2 = 14 kg
μ = 0.19
Angle is given by 5,12,23 triangle shown in figure.
Assume pulleys are massless.

What is the acceleration of mass m2 on the incline plane? (Positive acceleration to be up ramp)

Homework Equations




Mass 2:
T - m2g(\frac{5}{13}) - μm2g(\frac{12}{13}) = m2a2

Mass 1:
2T - m1g = m1a1

Pulley System:
a2 = -2a1

The Attempt at a Solution



Even though acceleration is assumed to be up the ramp, I drew my FBD with acceleration going down the ramp. I know that if my answer is negative it will be the opposite direction of what I assumed.

After I plugged the pulley equation into the mass 2 equation and then solved two equations with two unknowns:

T = 279.8 N

a1 = 7.15 \frac{m}{s^2}

a2 = 14.30 \frac{m}{s^2} (Initially this was a negative answer, which reversed my assumption of the direction)
 

Attachments

  • inclined plane.JPG
    inclined plane.JPG
    4.8 KB · Views: 474
Physics news on Phys.org

Homework Statement



I thought that my answers were correct but they are not. I would appreciate it if someone could check my work. I can't seem to find where I made my mistake!

I have also attached a scan of my free body diagrams and the equations that I came up with.

m1 = 33 kg
m2 = 14 kg
μ = 0.19
Angle is given by 5,12,13 triangle shown in figure.
Assume pulleys are massless.

What is the acceleration of mass m2 on the incline plane?

Homework Equations



These are the equations that I came up with from my free body diagrams:

Mass 2:
T - m2g(\frac{5}{13}) - μm2g(\frac{12}{13}) = m2a2

Mass 1:
2T - m1g = m1a1

Pulley System:
a2 = -2a1

The Attempt at a Solution



After I plugged the pulley equation into the mass 2 equation and then solved two equations with two unknowns:

T = 121.43 N

a1 = 2.45 \frac{m}{s^2}

a2 = 4.90 \frac{m}{s^2} (Initially this was a negative answer, which reversed my assumption of the direction)
 

Attachments

What makes you think the answer is incorrect? Do you have answers provided: perhaps they hold a clue?

You could check by simplifying the system - the pulley system offers a mechanical advantage in one direction ... which, and what does that mean?
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top