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Indefinite integral

  • Thread starter suprabay
  • Start date
  • #1
2
0

Homework Statement



∫(exp(6x))/(exp(12x)+25)dx

Homework Equations



answer: -arctan[5/exp(6*x)]/30

The Attempt at a Solution



honestly, don't know where to start. i was looking at another forum and tried to set u=exp(x) du=exp(x) and dx=du/u. plugging that in i got u^6/(u^12+25)*du/u. not sure where to go from there or if that is even the way to go.
 

Answers and Replies

  • #2
gabbagabbahey
Homework Helper
Gold Member
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Hi supraboy, Welcome to PF!:smile:

Try the substitution [tex]u=e^{6x}[/tex] instead :wink:
 
  • #3
139
12
Try setting u = e6x. Then du = 6e6x and e12x = u2.
 
  • #4
2
0
ok, setting u=e^6x du=6e^6x, then dx=du/6u?

then, it would be int(u/u^2+25)du

using the formula int(a^2+u^2) = (1/a)arctan(u/a) + C

i get, (1/5)arctan(e^6x/5)dx or (1/30)arctan(e^6x/5) + C

this is incorrect though because the answer is negative and it should be arctan(5/e^6x) instead of arctan(e^6x/5).

any ideas?
 
Last edited:
  • #5
139
12
You made a mistake with the substitution. Write your integral like this:
[tex] \int \frac{(e^{6x} dx)}{(e^{6x})^2 + 25} [/tex]
If [tex] u = e^{6x} [/tex], then [tex] e^{6x} dx = \frac{1}{6} du [/tex]. Try working from there.
 

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