Initial Acceleration of a Center of Mass

AI Thread Summary
To find the initial acceleration of the center of mass of a uniform rod released from an angle of 23.0° above the horizontal, one must calculate the torque exerted by gravity on the rod. The center of mass is located at half the length of the rod, which is 0.625 m. By applying the formula for angular acceleration, the relationship between angular acceleration and linear acceleration can be established using the equation αD = a, where D is the distance to the center of mass. This approach allows for determining the initial linear acceleration of the center of mass based on the calculated angular acceleration. Understanding these principles is crucial for solving the problem accurately.
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Homework Statement



A uniform rod of length 1.25 m is attached to a frictionless pivot at one end. It is released from rest from an angle θ = 23.0° above the horizontal.

PivotRod.gif


Find the magnitude of the initial acceleration of the rod's center of mass.


I keep getting the wrong answer. Please help with a push in the right direction.
 
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You can use the fact that the center of mass lies at 1/2 * L and that gravity grips the rod here. You can then use a simple geometric rule to find the force perpendicular to the rod, hence its initial acceleration.
 
You can calculate the torque exerted by gravity, and hence the angular acceleration of the rod. This can be related to the linear acceleration (of for instance the CoM) by the formula
\alpha D = a
where D is the distance to the point of interest (CoM in this example)
 
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