Initial vs. Final velocity of projectile with no net displacement

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When a ball is thrown and caught at the same height with constant horizontal velocity and no vertical displacement, its initial and final velocities are equal in magnitude but differ in direction. The vertical component of velocity changes sign, while the horizontal component remains constant. Therefore, although the speed is the same, the overall velocity is not, due to the change in direction. The vertical displacement equation confirms that the vertical velocity components are equal, but it does not apply to horizontal velocity. Thus, while the magnitudes are identical, the vectors are not the same.
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if a ball is thrown and caught at the same height with constant horizontal velocity and no vertical displacement is its initial and final velocity the same?

since v2y^2=v1y^2+2aDy, no displacement means final vertical velocity will be the same as initial,

since v2x=v1x, horizontal velocity will be the same, so v2=v1
 
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Velocity is a vector quantity.

The direction of the ball when it is caught is different from when it is thrown.
 
right, so at first it would be in one direction then a different direction but does the value change other than that?
 
The magnitude of the velocity (which is the speed) will be the same. The velocity, however, will be different because the vertical component of velocity will have changed sign.
 
PhysicsAdvice said:
if a ball is thrown and caught at the same height with constant horizontal velocity and no vertical displacement is its initial and final velocity the same?

since v2y^2=v1y^2+2aDy, no displacement means final vertical velocity will be the same as initial,

since v2x=v1x, horizontal velocity will be the same, so v2=v1


Yup ! It would be the same but you can't using the vertical displacement equation to prove the horizontal velocity.:smile:
 
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