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[SOLVED] Integrating with Change of variables -method
Solve by "Change of variables"-method ∫(dx)/(eˆx + eˆ(-x))
∫f(x)dx=∫f(x(t))*x'(t)dt
∫(dx)/(eˆx + eˆ(-x))=∫(eˆx)/(1 + eˆ2x) t=eˆx x=ln (t) (dt)/(dx)=t => dx=1/t dt
∫t/(tˆ2 + 1) * 1/t => ∫1/(tˆ2 + 1) = WRONG!
Where am I making a mistake? How do I know which term I should take as "t"? I have tried to read more in internet of this subject but couldn't find anything helpful. I read one topic here about this subject. The helper had used chain-method to solve this sort of problem but I couldn't understand it. Could someone help me to understand it? I'm just started my studies at university and my knowledge is very very limited. (Sorry my english, I'm finnish...)
Homework Statement
Solve by "Change of variables"-method ∫(dx)/(eˆx + eˆ(-x))
Homework Equations
∫f(x)dx=∫f(x(t))*x'(t)dt
The Attempt at a Solution
∫(dx)/(eˆx + eˆ(-x))=∫(eˆx)/(1 + eˆ2x) t=eˆx x=ln (t) (dt)/(dx)=t => dx=1/t dt
∫t/(tˆ2 + 1) * 1/t => ∫1/(tˆ2 + 1) = WRONG!
Where am I making a mistake? How do I know which term I should take as "t"? I have tried to read more in internet of this subject but couldn't find anything helpful. I read one topic here about this subject. The helper had used chain-method to solve this sort of problem but I couldn't understand it. Could someone help me to understand it? I'm just started my studies at university and my knowledge is very very limited. (Sorry my english, I'm finnish...)
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