Integration by partial fractions part. 2

sdoyle
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Homework Statement


\int\frac{e^x}{(e^x-2)(e^2x +1)} it should be e to the power of 2x



Homework Equations


Using substitution u=e^x, and then using partial fractions



The Attempt at a Solution


I have done this problem two separate ways. One with substitution and then partial fractions, and the other with just partial fractions. Both times I end with different coefficient values. I'm not sure if you can use both substitution and then partial fractions...
 
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In your equation (which I can't really read) you're missing the dx! What I recommend you do is a u substitution, but make sure you change all the things related to x to u. For example, u = e^x, then du = e^x * dx so when you substitute the e^2x on top becomes e^x (since one of them is used for the du) giving you:

(u du) / [(u-2)(u^2 + 1)]
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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