# Integration by parts help?

1. Aug 30, 2012

### Jay9313

1. The problem statement, all variables and given/known data

∫ln(2x+1) Integrate by parts

2. Relevant equations

I got xln(2x+1)+$\frac{1}2{}$ln(2x+1)-x+C

3. The attempt at a solution

The solution is $\frac{1}{2}$(2x+1)ln(2x+1)-x+C

I know the answers are the same,but it's bugging me that I can't simplify the first answer I got to the second answer. Can someone explain it to me?

2. Aug 30, 2012

### Villyer

Look at the first two terms of your answer. Is there a common factor there that you can pull out?

3. Aug 30, 2012

### Jay9313

ln(2x+1) But I don't see how that will help?

4. Aug 30, 2012

### Jay9313

Oh, you can pull the term out, substitute your x from your u substitution, combine some terms, and you get it! Thanks!

5. Aug 30, 2012