Integration by parts, how to find int 1/(x (ln 3)^2) dx

Thread starter intenzxboi
Start date Feb 13, 2009
Tags

Dx Integration Integration by parts parts

Feb 13, 2009

intenzxboi

Homework Statement

int dx / (x (ln 3)^3)

can someone tell me how to start this problem what's my u and dv ??

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Feb 13, 2009

Dick

Science Advisor

Homework Helper

You've got to mean dx/(x*ln(x)^3). Just do u=ln(x). That's all.

Feb 13, 2009

intenzxboi

opps actually problem is int dx / (x (ln x)^3)

so u = ln x
du= 1/x dx

int 1/ u^3 dx

Feb 13, 2009

Dick

Science Advisor

Homework Helper

1/u^3 du. Not dx.

Feb 13, 2009

intenzxboi

right.. thanks

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