Integration by Parts: Finding the Center of Gravity in a Fan Blade

In summary, the conversation discussed using the integration by parts formula to determine the centre of gravity inside a fan blade. The formula used was v.du/dx = v.u - u.dv/dx, with integral limits of 0 to 20. However, there was a discrepancy in the solution as the correct answer should be a number, not a formula in x. Additionally, there may be an issue with the calculation as u was incorrectly given as 0.3 cos x instead of -0.3 cos x.
  • #1
smell5
9
0
Basically I have answered a question using the integration by parts formulae to work out the centre of gravity inside a fan blade using :-

v.du/dx = v.u - u. dv/dx with the integral limits of 0 ==> 20

when v = x then dv/dx =1
when du/dx = 0.3 sinx then u = 0.3cos x

and sub this into the equation to get x(0.3sinx) = x(0.3cosx) - 0.3cosx(1)

Can anyone see any issue with this because he's marked it wrong?
 
Physics news on Phys.org
  • #2
Well, one problem is that if du/dx= 0.3 sin x then u= -03 cos x, not 0.3 cos x

And you say the integral is from 0 to 20. Did you evaluate between those two limits? The correct answer is a number, not a formula in x.
 

Related to Integration by Parts: Finding the Center of Gravity in a Fan Blade

What is integration by parts?

Integration by parts is a technique used in calculus to find the integral of a product of two functions. It is based on the product rule of differentiation and involves breaking down the integral into smaller parts.

How is integration by parts used?

Integration by parts is used to find the integral of a product of two functions that cannot be easily integrated by other methods. It is particularly useful when one of the functions is a polynomial and the other is a trigonometric, exponential, or logarithmic function.

What is the formula for integration by parts?

The formula for integration by parts is ∫u dv = uv - ∫v du, where u and v are the two functions being multiplied together, and du and dv are their respective differentials.

What is the purpose of integration by parts?

The purpose of integration by parts is to simplify the integration of complex functions by breaking them down into smaller parts. It also allows for the integration of functions that cannot be easily integrated by other methods.

What are the limitations of integration by parts?

Integration by parts can only be used when one function is differentiable and the other is integrable. It is also not always successful in finding the integral and may require multiple iterations to find a solution.

Similar threads

  • Calculus and Beyond Homework Help
Replies
3
Views
1K
  • Calculus and Beyond Homework Help
Replies
22
Views
1K
  • Calculus and Beyond Homework Help
Replies
19
Views
803
  • Calculus and Beyond Homework Help
Replies
15
Views
802
  • Calculus and Beyond Homework Help
Replies
1
Views
784
  • Calculus and Beyond Homework Help
Replies
8
Views
783
  • Calculus and Beyond Homework Help
Replies
3
Views
973
  • Calculus and Beyond Homework Help
Replies
1
Views
899
  • Calculus and Beyond Homework Help
Replies
10
Views
1K
Back
Top