Integration by Parts: Solve y(1+y^2)^1/2 dy

[Song]

integral y(1+y^2)^1/2 dy

can someone help me with this?

Thanks.

 

[Song]

trigonometirc sub.

 

[Bernie Hunt]

Wouldn't this solve easier with u substituion?
u = 1+y^2
du = 2y dy

Solution is 1/3(1+y^2)^3/2

If you want integration by parts, multiply it out and make u to be y so that du is 1.

By trig you'll need to substitute tan because the problem is + Y^2.

Bernie