Integration involving a square root function.

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Homework Help Overview

The discussion revolves around the integration of the function sqrt(1/4 + t^2 + t^4) over the interval from -1 to 1. Participants are exploring methods to approach this integration problem, particularly focusing on the manipulation of the expression under the square root.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the possibility of factorizing the expression and the implications of pulling constants out of the square root. Questions arise regarding the behavior of the absolute value in the context of the integration.

Discussion Status

Some participants have offered insights into recognizing the structure of the expression under the square root, while others express uncertainty about the reasoning behind these manipulations. There is a mix of understanding and confusion regarding the steps involved in simplifying the integral.

Contextual Notes

Participants mention a solutions manual that presents a method they are not familiar with, indicating a potential gap in knowledge or experience with similar integration techniques.

NewtonianAlch
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Homework Statement


Integrate:

sqrt(1/4 + t^2 + t^4)

The Attempt at a Solution



I'm really not sure on how to go about integrating this, it's actually integrate from -1 to 1, the solutions manual has a method I'm not familiar with. I thought of factorising it first, although doing that hasn't made it any easier.
 
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I stared at it blankly for a little bit. But then I asked wolfram for the steps and said aha, why didn't I see that. If you pull the 1/4 out, you should recognize that 4t^4+4t^2+1 is the square of 2t^2+1. So you are integrating |2t^2+1|/2. But the absolute value goes away since 2t^2+1 is never negative.
 
I saw that in Wolfram too, although I didn't quite understand what was happening there.

So are you saying that pulling out the 1/4 from a square root doubles it when you pull it out? Or any other number for that matter.
 
Hmm, I think I see what you mean now, since the root of 1/4 is 0.5 you can take that out.

Interesting, doubt I'd have figured out all that myself without some help, thanks.
 

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