Integration problem about household electricity

AI Thread Summary
The discussion centers on understanding a problem related to household electricity and calculating the RMS voltage from a given equation. The equation for voltage is E(t) = 155sin(120πt), and participants clarify that the RMS voltage can be found using an integral to average the square of E(t) over one cycle. The formula provided is A = (1/T) ∫[0 to T] E(t)^2 dt, followed by taking the square root. After receiving guidance, the original poster successfully solved the problem. The conversation highlights the importance of understanding RMS calculations in electrical engineering.
Stevecgz
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I don't understand what the following problem is asking for:

Household electricity is supplied in the form of alternating current that varies from 155 V to -155 V with a frequency of 60 cycles per second (Hx). The voltage is thus given by the equation:

E(t) = 155\sin(120\pi t)

where t is the time in seconds. Voltmeters read the RMS (root-mean-square) voltage, which is the square root of the average value of [E(t)]^2 over one cycle.

a. Calculate the RMS voltage of household current.

b. Many electric stoves requre an RMS voltage of 220 V. Find the corresponding amplitude A needed for the voltage E(t)=A\sin(120\pi t).

If someone could explain to me what they are asking for it would be appreciated.

Steve
 
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Use an integral to calculate to calculate the average

<br /> A = \frac{1}{T} \int_{0}^{T} E \left( t \right)^2 dt, <br />

where T is the time taken for one period, and then take the square root to find the RMS value of the voltage.

Working from right to left, RMS means: first square E, then take the average, then take the square root.

Regards,
George
 
Use an integral to calculate to calculate the average

<br /> A = \frac{1}{T} \int_{0}^{T} E \left( t \right)^2 dt, <br />

where T is the time taken for one period, and then take the square root to find the RMS value of the voltage.

Working from right to left, RMS means: first square E, then take the average, then take the square root.

Regards,
George
 
Thanks George, I was able to solve the problem now.

Steve
 
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