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andipandi
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A simple circuit with 2 batteries and a resistor connected in series. The positive terminals are connected to each other via a 4.5 resistor. Their emfs and internal resistances are below. What is the resultant emf?
battery 1: ε=6V r=1Ω
battery 2: ε=24V r=0.5Ω
resistor connecting the two batteries is 4.5Ω
(I've attached a picture of the circuit diagram)
The answer is 18V. I know that resultant emf =ε - Ir. But I have no idea how to achieve an answer when their are two batteries present, let alone connected in opposition. I've spent the past two hours research books and the internet with nothing to show of it. The only way I can see to get 18V would be to simply minus emf of battery 1 from battery2, if this is correct rather than a coincidence, what is the rule behind it?
battery 1: ε=6V r=1Ω
battery 2: ε=24V r=0.5Ω
resistor connecting the two batteries is 4.5Ω
(I've attached a picture of the circuit diagram)
The answer is 18V. I know that resultant emf =ε - Ir. But I have no idea how to achieve an answer when their are two batteries present, let alone connected in opposition. I've spent the past two hours research books and the internet with nothing to show of it. The only way I can see to get 18V would be to simply minus emf of battery 1 from battery2, if this is correct rather than a coincidence, what is the rule behind it?
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