Is the Calculation of Strain Due to Own Weight Correct?

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The discussion centers on the calculation of elongation due to an object's own weight, with a participant questioning the accuracy of their result, which suggests an elongation of 4320 meters. Concerns are raised about potential errors in unit conversions, particularly regarding the modulus of elasticity. Participants emphasize the importance of verifying calculations and ensuring proper unit usage. The original length of the object is noted as 150 meters, raising doubts about the feasibility of the calculated elongation. The conversation highlights the need for careful review in engineering calculations.
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Homework Statement


for the elongation due to its own weight , i suspect the calculation of elonation due to its own weight is wrong ...

Homework Equations

The Attempt at a Solution


I think it should be (3456.3825)(75) / (300x10^-6)(200x10^3) = 4320m = 4320x10^3 mm , right ? [/B]
 

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Four kilometers?!
 
Bystander said:
Four kilometers?!
anything wrong with my calculation ?
 
Given that the original length is only 150 meters? What's your conclusion?
 
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Bystander said:
Given that the original length is only 150 meters? What's your conclusion?
sorry , here's the second image
 

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You've made mistake(s) in the conversion to meters (handwritten work, 2nd image). Try it again.
 
Bystander said:
You've made mistake(s) in the conversion to meters (handwritten work, 2nd image). Try it again.
I'm looking at the units of E in his calculation, and it doesn't seem correct to me.
 
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