yogi said:
Jesse - Do i believe in Lorentz invarience - yes and no - how is that for a fence sitter.
I don't think you understand, yogi. "Lorentz-invariance" is just a mathematical property of certain equations, deciding whether or not a given equation shows Lorentz-invariance is as straightforward as deciding whether it's a polynomial.
Let's first consider the related concept of "Galilei-invariance", which is a bit simpler mathematically. The Galilei transform for transforming between different frames in Newtonian mechanics looks like this:
x' = x - vt
y' = y
z' = z
t' = t
and
x = x' + vt'
y = y'
z = z'
t = t'
To say a certain physical equation is "Galilei-invariant" just means the form of the equation is unchanged if you make these substitutions. For example, suppose at time t you have a mass m_1 at position (x_1 , y_1 , z_1) and another mass m_2 at position (x_2 , y_2 , z_2 ) in your reference frame. Then the Newtonian equation for the gravitational force between them would be:
F = \frac{G m_1 m_2}{(x_1 - x_2 )^2 + (y_1 - y_2 )^2 + (z_1 - z_2 )^2}
Now, suppose we want to transform into a new coordinate system moving at velocity v along the x-axis of the first one. In this coordinate system, at time t' the mass m_1 has coordinates (x'_1 , y'_1 , z'_1) and the mass m_2 has coordinates (x'_2 , y'_2 , z'_2 ). Using the Galilei transformation, we can figure how the force would look in this new coordinate system, by substituting in x_1 = x'_1 + v t', x_2 = x'_2 + v t', y_1 = y'_1, y_2 = y'_2, and so forth. With these substitutions, the above equation becomes:
F = \frac{G m_1 m_2 }{(x'_1 + vt' - (x'_2 + vt'))^2 + (y'_1 - y'_2 )^2 + (z'_1 - z'_2 )^2}
and you can see that this simplifies to:
F = \frac{G m_1 m_2 }{(x'_1 - x'_2 )^2 + (y'_1 - y'_2 )^2 + (z'_1 - z'_2 )^2}
Comparing this with the original equation, you can see the equation has exactly the same form in the primed coordinate system as in the unprimed coordinate system. This is what it means to be "Galilei invariant". More generally, if you have
any physical equation which computes some quantity (say, force) as a function of various space and time coordinates, like f(x,y,z,t) [of course it may have more than one of each coordinate, like the x_1 and x_2 above, and it may be a function of additional variables as well, like m_1 and m_2 above] then for this equation to be "Galilei invariant", it must satisfy:
f(x'+vt',y',z',t') = f(x',y',z',t')
So in the same way, if we look at the Lorentz transform:
x' = \gamma (x - vt)
y' = y
z' = z
t' = \gamma (t - vx/c^2)
where \gamma = 1/\sqrt{1 - v^2/c^2}
and
x = \gamma (x' + vt')
y = y'
z = z'
t = \gamma (t' + vx'/c^2)
Then all that is required for an equation to be "Lorentz-invariant" is that it satisfies:
f( \gamma (x' + vt' ), y' , z', \gamma (t' + vx' /c^2 ) ) = f(x' ,y' ,z' , t')
There may be some more sophisticated way of stating the meaning of Lorentz-invariance in terms of group theory or something, but if an equation is Lorentz-invariant, then it should certainly satisfy the condition above. Maxwell's laws of electromagnetism would satisfy it, for example. And it's pretty easy to see that if it satisfies this mathematical condition, then the equation
must have the same form when you transform into a different inertial frame using the Lorentz transform. So this is enough to show beyond a shadow of a doubt that
given Lorentz-invariant fundamental laws, all the fundamental laws must work the same in any inertial reference frame, and if you know the equation for a given law as expressed in some particular inertial frame (the rest frame of the center of the earth, for example) then it is a straightforward mathematical question as to whether or not this equation is Lorentz-invariant, it's not an experimental issue (the only experimental issue is whether that equation makes correct predictions in the first place). Do you disagree with any of this?
yogi said:
Is it always permissible to shift from the frame in which the clocks were syncronized to make interrogations of the orbiting clocks? I think not.
The satellite clocks will not be seen as running at a uniform rate in another frame in motion wrt to the non-rotating Earth centered reference frame.
Uh, why does this mean it's not "permissible" to shift into another frame? That's the whole point, that different frames disagree about whether a given set of clocks is running at a uniform rate. But all frames will agree on all physical questions like what two clocks will read at the moment they meet at a single location in space. You need to define what you mean by "permissible", when physicists use this term all it means is that you can use the same laws of physics in another frame and all your predictions about physical questions will still be accurate (that's why it's not 'permissible' to use the ordinary rules of SR for inertial frames in a non-inertial coordinate systems, because you would make
wrong predictions if you did this). Given Lorentz-invariant laws, this is automatically going to be true for all inertial frames.
Also, the GPS clocks are
programmed to adjust themselves so that they tick at a constant rate in the frame of the earth. My other point was that this is a completely arbitrary choice made by the designers, you could just as well design the orbiting GPS clocks to adjust themselves so that they tick at a constant rate in the frame of an inertial observer moving at 0.99c relative to the earth. Would you then say it is not "permissible" to analyze these clocks in the rest frame of the earth, since they would not be running at a uniform rate in the Earth's frame?