Is the Gas Heated and Cooled Equally in Phase C->D on the Pressure/Volume Graph?

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During the phase C to D on the pressure/volume graph, the gas is indeed heated as it does work on the surroundings, even though the product of pressure and volume remains constant. The discussion clarifies that this process is characteristic of an isothermal process for ideal gases, where heat gained equals the work done by the gas, resulting in no change in internal energy. There is a distinction made between heating and cooling, indicating that if work is done on the gas, it must lose heat to maintain a constant temperature. The participants agree that the heating process from C to D does not require external work but involves the gas performing work on the environment. Understanding these thermodynamic principles is crucial for analyzing gas behavior in different phases.
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It is said that during the phase C->D, the gas is heated. I can see at some points, the pressure*volume is higher than the initial one, which is 10*2=20, but its also lower at some points. So as it starts off as 10*2, and ends as 2*10, I would say that it is both heated and cooled equally. Where am I wrong?

Thanks in advance !
 
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Or is the statement wrong?
 
Being heated means that heat is transferred to the gas or other object, but this does not necessarily mean that the temperature increases. When you make boiled egg, the water is heated but the temperaure of the water remains 100 °C.
The process from B to C looks an isotherm expansion. The gas takes on heat but does work, equal to this heat and the temperature does not change during the process.

ehild
 
B to C actually looks more of an isobaric to me. Since pressure is constant and volume increases, that means the temperature must increase aswell.
And I still can't see how C to D must be heated. The pressure and volume multiplication is the same in both C and D, so I can't really see why the gas would need any outside work done, as in heating it?

Thanks in advance,
fawk3s
 
fawk3s said:
And I still can't see how C to D must be heated. The pressure and volume multiplication is the same in both C and D, so I can't really see why the gas would need any outside work done, as in heating it?


fawk3s
During the process from C to D (it was a mistake writing BC in my previous post) the gas does not need work from the outside world, but does work on it.
PV=constant is characteristic to an isothermal process in case of ideal gases. During such process, the heat gained is equal to the work done by the gas, and the internal energy does not change.

ehild
 
Let me see if I got this straight. In the process from C to D, heat is needed to do work on the outside world. Right?
But a follow up question. If the process was from D to C, the heat or the energy would need to be taken away from the gas in order to do the opposite work, as in cooled?
 
If some outer force does work on the gas, the gas most be cooled in order to keep its temperature constant.

ehild
 
Think I get it. Thanks ehild !
 
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