Is the Plastic Ball's Charge Positive or Negative in a Uniform Electric Field?

AI Thread Summary
The discussion centers on determining the charge of a plastic ball in a uniform electric field. It is established that the ball's charge is positive, as indicated by its equilibrium position when the string makes a 15-degree angle with the vertical. Participants analyze the forces acting on the ball, including gravitational force and electrostatic force, leading to the conclusion that the tangent of the angle represents the ratio of these forces. The formula q = mg * tan(15) / E is derived to calculate the net charge, with the expected answer being 5.3 x 10^-7 C. The conversation highlights confusion around the direction of forces and the application of trigonometric relationships in solving the problem.
redhawks
Messages
6
Reaction score
0

Homework Statement


A 2g plastic ball is suspended by a 2cm string in a uniform electric field of 1.0 x 10^4 N/C (the arrows point to the right)

a) is the balls charge positive of negative?
(B) If the ball is in equilibrium when the string makes a 15 degree angle with the vertical, what is the net charge. (15 degree angle going towards where the E arrows point)


Homework Equations


E=Ck((q1*q2)/r^2)

The Attempt at a Solution


a) i know it is positive
b) i did work but i can never get the right answer which is 5.3*10^-7C
 
Physics news on Phys.org
I'm not sure which direction your suspended object is going, but for b) consider the angle of the string. Won't it be the sum of m*g down and the electrostatic force horizontally? So isn't tan15 then the ratio of the 2 forces?
 
its going right
 
i don't understand. help, pleaseee
 
redhawks said:
i don't understand. help, pleaseee

So isn't tan15 then the ratio of the 2 forces?

F = q*E

and

q*E/(m*g) = tan15

q = m*g*tan15/E

Isn't that all there is to it?
 
redhawks said:
i don't understand. help, pleaseee

The force on the charged ball due to electric field is Eq, and weight of the ball is mg. The ratio of the forces is Eq/mg = tanθ. Solve for q.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top