Is this question dealing with law of conservation of momentum?

AI Thread Summary
The discussion revolves around a physics problem involving a man moving in a canoe and its relation to the law of conservation of momentum. The scenario describes a 75-kg man moving forward at 0.50 m/s in a 120-kg canoe initially at rest. Participants express confusion about applying the momentum conservation equation, particularly in determining the canoe's resulting motion. The equation m1v1 + m2v2 = m1v1' + m2v2' is highlighted, but users struggle with identifying the correct variables for the initial and final states. Understanding how to apply the conservation of momentum is crucial for solving the problem effectively.
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Homework Statement


A 75-kg man sits in the back of a 120-kg canoe that is at rest in a still pond. If the man beings to move forward in the canoe at .50m|s relative to the shore, what happens to the canoe?


Homework Equations


The equation they gave me is m1v1+m2v2 = m1v1'+m2v2'
I don't get it.


The Attempt at a Solution


I didn't really make an attempt. All I have on the paper is
(120 kg)(.50m|s) + ... I don't know what to put there. If it's even right!
 
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You have 2 different parts. At rest and moving, aka before and after, aka primed and unprimed.
 
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