Is This the Correct Solution for Kirchhoff's Loop Problem?

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SUMMARY

The discussion focuses on solving Kirchhoff's Loop Problem by determining the currents I1, I2, and I3 using the equations derived from the circuit diagram. The equations provided are: 12y - 24 + 35x = 0, 35x + 34z - 18 = 0, and x = y + z. The calculated values are I1 = 0.508 A, I2 = 0.511 A, and I3 = 0.0029 A, which are confirmed as correct. The solution emphasizes the application of the current rule and the use of potential differences in the nodes.

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shrabastee
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Homework Statement


We are to find I1, I2 and I3 in the diagram.


Homework Equations


These are the three equations I got. I need to know if they're correct.
x=I1
y=I2
z=I3

12y-24+35x=0
35x+34z-18=0
x=y+z

The Attempt at a Solution


Values I got on solving:
I1=0.508
I2=0.511
I3=0.0029

(Note: r=1 ohm)

kindly tell me if this is correct! :)
 

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Sign convention followed:

In the direction of the current=positive
Negative to positive plate=negative
 
shrabastee said:
Sign convention followed:

In the direction of the current=positive
Negative to positive plate=negative

The solution is correct. I almost never use the voltage/loop rule.

If you give the node at the top an unknown potential V, and the node at the bottom a potential
0, you only have to use the current rule once to get a single equation for V.
 

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