Isobaric Process: Fill in ΔP for Homework Equation

AI Thread Summary
In an isobaric process, the pressure remains constant, meaning the change in pressure (ΔP) is zero. The discussion clarifies that ΔP is calculated as the difference between final pressure (Pf) and initial pressure (Pi). Since Pf and Pi are equal in this scenario, ΔP must be 0. Participants emphasize the importance of understanding the definitions and meanings behind the equations used in thermodynamics. Ultimately, the correct value for ΔP in this case is confirmed to be zero.
traveler7
Messages
8
Reaction score
0

Homework Statement



Pf
429

Q
-754

ΔU
819

The table above shows the measurements taken while an ideal gas underwent an ISOBARIC process. Fill in the appropriate values for the table below.

ΔP=?

Homework Equations



Q= ΔU+W=ΔU=PΔV

The Attempt at a Solution



I don't know how to go about solving this
 
Physics news on Phys.org
traveler7 said:

The Attempt at a Solution



I don't know how to go about solving this

For an isobaric process, what is constant? Hence what is ΔP ?
 
Do you know what isobaric means? If not, look it up.
 
isobaric means same pressure

but i tried 429 and that didnt work

Is the difference in pressure 0? so 0 would be delta p?
 
traveler7 said:
isobaric means same pressure

but i tried 429 and that didnt work

Is the difference in pressure 0? so 0 would be delta p?

Right so if it means the same pressure, then the final pressure and the initial pressure are the same. So the change in pressure would be 0.
 
It sounds like you're just guessing. You need to understand that the equations have meanings and the quantities that appear in them have precise definitions. If you don't know what ΔP represents, the first thing you need to do is figure that out.

In this case, ΔP=Pf-Pi represents the change in pressure between the initial and final states, so your answer of 429 (units?) would mean that the pressure increased by that amount. Clearly, this doesn't meet the condition of an isobaric process, where the pressure is, by definition, constant. Since the pressure is constant, you know that Pi=Pf, so ΔP=0.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top