Isobaric Process: Fill in ΔP for Homework Equation

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Homework Help Overview

The discussion revolves around an isobaric process involving an ideal gas, where participants are tasked with determining the change in pressure (ΔP) based on given values in a table. The context includes understanding the implications of the isobaric condition on pressure changes.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of an isobaric process and its implications for pressure changes, questioning what ΔP represents in this context. Some express uncertainty about how to approach the problem, while others attempt to relate the concept to the provided values.

Discussion Status

The discussion is ongoing, with some participants providing insights into the meaning of isobaric processes and the implications for ΔP. There is a recognition that if pressure is constant, then ΔP should be zero, but this understanding is still being debated among participants.

Contextual Notes

Some participants express confusion over the definitions and calculations involved, indicating a need for further clarification on the relationships between the variables in the equations provided.

traveler7
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Homework Statement



Pf
429

Q
-754

ΔU
819

The table above shows the measurements taken while an ideal gas underwent an ISOBARIC process. Fill in the appropriate values for the table below.

ΔP=?

Homework Equations



Q= ΔU+W=ΔU=PΔV

The Attempt at a Solution



I don't know how to go about solving this
 
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traveler7 said:

The Attempt at a Solution



I don't know how to go about solving this

For an isobaric process, what is constant? Hence what is ΔP ?
 
Do you know what isobaric means? If not, look it up.
 
isobaric means same pressure

but i tried 429 and that didnt work

Is the difference in pressure 0? so 0 would be delta p?
 
traveler7 said:
isobaric means same pressure

but i tried 429 and that didnt work

Is the difference in pressure 0? so 0 would be delta p?

Right so if it means the same pressure, then the final pressure and the initial pressure are the same. So the change in pressure would be 0.
 
It sounds like you're just guessing. You need to understand that the equations have meanings and the quantities that appear in them have precise definitions. If you don't know what ΔP represents, the first thing you need to do is figure that out.

In this case, ΔP=Pf-Pi represents the change in pressure between the initial and final states, so your answer of 429 (units?) would mean that the pressure increased by that amount. Clearly, this doesn't meet the condition of an isobaric process, where the pressure is, by definition, constant. Since the pressure is constant, you know that Pi=Pf, so ΔP=0.
 

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