Kinetic Friction Homework: Solve for Acceleration of 880 N Crate

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SUMMARY

The discussion centers on calculating the acceleration of an 880 N crate being pulled with a force of 395 N at a 25° angle above the horizontal, with a coefficient of kinetic friction of 0.25. The solution involves determining the normal force (Fn) using the weight of the crate and the sine of the applied force angle. The mass (m) is calculated by dividing the weight of the crate by the acceleration due to gravity (9.8 m/s²), followed by applying the equation ma = uFn to find the acceleration (a).

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  • Knowledge of forces and friction coefficients
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  • Familiarity with basic trigonometry
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Homework Statement


A 880 N crate is being pulled across a level floor by a force F of 395 N at an angle of 25° above the horizontal. The coefficient of kinetic friction between the crate and the floor is 0.25. Find the magnitude of the acceleration of the crate.


Homework Equations


not quite sure?? was absent


The Attempt at a Solution


dont know where to begin
 
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wow nevermind solved it...

found Fn first using the N of the crate and sin of the applied force, then i plugged that into

ma=uFn and found m by dividing 880 by 9.8 then just solved for a
 

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