Kinetic Friction Homework: Solve for Acceleration of 880 N Crate

AI Thread Summary
To find the acceleration of an 880 N crate being pulled with a 395 N force at a 25° angle, the normal force (Fn) must first be calculated using the weight of the crate and the vertical component of the applied force. The coefficient of kinetic friction is 0.25, which is used in the equation ma = uFn to determine the net force acting on the crate. The mass of the crate is derived by dividing its weight by the acceleration due to gravity (9.8 m/s²). After substituting the values into the equations, the acceleration can be solved. The process emphasizes understanding the relationship between forces, friction, and acceleration.
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Homework Statement


A 880 N crate is being pulled across a level floor by a force F of 395 N at an angle of 25° above the horizontal. The coefficient of kinetic friction between the crate and the floor is 0.25. Find the magnitude of the acceleration of the crate.


Homework Equations


not quite sure?? was absent


The Attempt at a Solution


dont know where to begin
 
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wow nevermind solved it...

found Fn first using the N of the crate and sin of the applied force, then i plugged that into

ma=uFn and found m by dividing 880 by 9.8 then just solved for a
 
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