Kirchhoff's Rule Cap-monster maze

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The discussion revolves around solving two electrical circuit problems: the cap-monster maze and the res-monster maze. For the cap-monster maze, the initial calculation of charge was stated as 60 nanoCoulombs, but it was corrected to 15 microCoulombs. In the res-monster maze, the current was initially calculated as 4A, but it was clarified that the correct answer is 2A due to the consideration of the battery's positive sign. Participants engaged in lighthearted banter while correcting each other's calculations. The conversation emphasizes the importance of careful analysis in circuit problems.
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Well, the attachments says it all, the cap-monster and res-monster maze. I want to know if I made a right decision about my answer.

Cap-monster maze

ξ - q/C = 0

Then q = 60(nano)Coulomb.

Res-monster Maze

1 - ξ2 - ξ3 - ξ4 + IR = 0

I = 4A.

Am I right?
 

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Hi Mastur! :smile:

oooh, they're fun! :biggrin:
Mastur said:
Cap-monster maze

ξ - q/C = 0

Then q = 60(nano)Coulomb.

yes (except for the nano)
Res-monster Maze

1 - ξ2 - ξ3 - ξ4 + IR = 0

nooo :wink:
 
I already got the Res-monster maze.

The problem is the one battery, which will have a positive sign. So the answer is 2A. :)

And what's with Nano? Hmm? But my answer is correct, right?

Naah, I got it. It's MICRO, not NANO, right? hahaha
 
he he he :biggrin:
 
the answer for the cap-monster cage is 15 micro coulombs. don't feel like explainin it cause I am a lazy bum but you should def trust me!
 
garbagesocray

"the answer for the cap-monster cage is 15 micro coulombs. don't feel like explainin it cause I am a lazy bum but you should def trust me!"
You are wrong garbagesocray . Try considering a loop in which there is only the capacitor C and the Battery(s).
Happy Solving :)
 
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