Lagrangian mechanics: Kinetic energy of a bead sliding along a bent wire

wdednam
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Homework Statement



Determine the kinetic energy of a bead of mass m which slides along a frictionless wire bent in the shape of a parabola of equation y = x2. The wire rotates at a constant angular velocity \omega about the y-axis.

Homework Equations



T = \frac{1}{2}m(\dot{x}^2 + \dot{y}^2 + {x}^2\omega^2)

The Attempt at a Solution



The above equation represents my attempt to write down the kinetic energy of the system in an appropriate coordinate system. After this I eliminated \dot{y} in favour of \dot{x} using y = x2 and got:

T = \frac{1}{2}m(\dot{x}^2 + 4{x}^2\dot{x}^2 + {x}^2\omega^2)

Does this look right to anyone? The book (study guide) I'm using was unfortunately compiled by my University and no answers are supplied to end-of-chapter problems. This problem comes out of the first chapter of my study guide and all the problems there basically involves writing down a correct expression for the Lagrangian/Kinetic Energy.

Thanks in advance for any help.
 
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wdednam said:
Determine the kinetic energy of a bead of mass m which slides along a frictionless wire bent in the shape of a parabola of equation y = x2. The wire rotates at a constant angular velocity \omega about the y-axis.

T = \frac{1}{2}m(\dot{x}^2 + 4{x}^2\dot{x}^2 + {x}^2\omega^2)

Does this look right to anyone?
It looks right to me. I am, of course, assuming, as you have apparently done as well, that x is the distance from the y-axis, and not simply the Cartesian x-coordinate.
 
turin said:
It looks right to me. I am, of course, assuming, as you have apparently done as well, that x is the distance from the y-axis, and not simply the Cartesian x-coordinate.

Hi Turin,

Thanks a lot for the help!

Yes, x does represent the distance from the y-axis, but I'm wondering if it wouldn't have been better to use cylindrical coordinates, z and r for y and x respectively, instead?
 
wdednam said:
Thanks a lot for the help!
I didn't even do anything, but, you're welcome. :)


wdednam said:
... I'm wondering if it wouldn't have been better to use cylindrical coordinates, z and r for y and x respectively, instead?
Of course, those are just letters, and what we have both implicitly assumed is that these ARE, in fact, cylindrical coordinates (in disguise), in the way that you have identified. I don't know why the author decided to use those letters as opposed to the standard \rho and z, but that was the author's decision, not ours.
 
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