(adsbygoogle = window.adsbygoogle || []).push({}); A student takes 0.45kg of ice. The ice is initally at -23'C. She heats the sample in an oven until the temp is 134'C.

a). What is the NRG needed to heat the ice to its melting point?

b). What is the NRG needed to change the solid ice into liquid water?

c). What is the NRG needed to heat the liquid water to its boiling point?

d). What is the NRG needed to change the liquid water to steam?

e). What is the NRG needed to heat the steam to 134'C?

f). Draw a graph with the temp of the sample in Kelvin on y axis, and NRG absorbed in Joules by the sample on the x axis.

Equations of use:

Q=mc(change in T)

Q=mL

a) (.45kg) (4.2x10^3 J/kg) (-23'C)=-4.3x10^6 J

b) (.45kg) (3.3x10^5 J/kg) = 1.5x10^5 J

c) (.45kg) (3.3x10^5 J/kg) (134'C) = 1.2x10^7 J

d) (.45kg) (2.3x10^6 J/kg) = 1.0x10^6 J

e) (.45kg) (2.3x10^6 J/kg) (134'C) = 1.4x10^8 J

f) I have ice drawn in a straight/horizontal line, then water drawn in a linear line followed by a straight/horizontal line, then steam in a linear line, then boiling in a straight/horizontal line.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Latent heat of Fusion Lab

**Physics Forums | Science Articles, Homework Help, Discussion**