Calculating the Ratio of Planetary Orbital Periods

AI Thread Summary
The discussion centers on calculating the ratio of the orbital periods of two planets, A and B, where planet B has double the mass and a semi-major axis twice that of planet A. The initial attempt incorrectly included the mass of the planets in the calculations, leading to an erroneous conclusion. It was clarified that according to Kepler's Third Law, the mass of the planets does not affect the ratio, as the relevant mass in the equation is that of the Sun. The correct approach shows that the ratio of the orbital periods is determined solely by the semi-major axes. Ultimately, the ratio of the orbital period of planet B to that of planet A is 2.
lizzyb
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Homework Statement



Two planets A and B, where B has twice the mass of A, orbit the Sun in elliptical orbits. The semi-major axis of the elliptical orbit of planet B is two times larger than the semi-major axis of the elliptical orbit of planet A.

What is the ratio of the orbital period of planet B to that of planet A?

Homework Equations



T^2 = (\frac{4 \pi^2}{G M}) r^3


The Attempt at a Solution



M_B = 2 M_A
a_B = 2 a_A
\frac{T_B}{T_A} = \frac{\sqrt{\frac{4 \pi^2}{G 2 M_A} 8 a_A^3}}{\sqrt{\frac{4 \pi^2}{G M_A} a_A^3}} = \sqrt{\frac{8}{2}} = \sqrt{ 4 } = 2
but that was wrong. ?
 
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lizzyb said:

Homework Equations



T^2 = (\frac{4 \pi^2}{G M}) r^3


The Attempt at a Solution



M_B = 2 M_A
a_B = 2 a_A
\frac{T_B}{T_A} = \frac{\sqrt{\frac{4 \pi^2}{G 2 M_A} 8 a_A^3}}{\sqrt{\frac{4 \pi^2}{G M_A} a_A^3}} = \sqrt{\frac{8}{2}} = \sqrt{ 4 } = 2
but that was wrong. ?
Planetary Mass is not a factor. Kepler's Third law states that T^2/a^3 is the same for all planets. The M in your equation is the mass of the sun.

AM
 
thank you.
 
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