Light waves and intereference patterns

AI Thread Summary
When shining two flashlights on a wall, no interference pattern is observed because the light waves from the two sources are not coherent and do not interact. For interference to occur, the light waves must be in sync, allowing for constructive or destructive interference. The mathematical representation of this phenomenon involves calculating the probability distribution of the combined wavefunctions, which reveals that without coherence, the interference terms vanish. Using a single light source ensures that the phases are identical, leading to observable interference patterns. Thus, the lack of interference with two flashlights stems from their incoherent nature.
kirsten_2009
Messages
136
Reaction score
2

Homework Statement


[/B]
You shine two flashlights on a wall. Why don’t you see an interference pattern?

Homework Equations

The Attempt at a Solution



Actually, I thought you would have seen an interference pattern but if you don’t then it’s probably because the waves of light of the two flashlights are not interacting with each other. In other words, they are not adding up as constructive interference or cancelling each other out by destructive interference so they must not be in sync and so the waves of both flashlights make it to the wall with no “interruptions”. If the waves of the two flashlights were exactly in sync then I presume you would see an interference pattern on the wall.
 
Physics news on Phys.org
To understand this just find the probability distribution of a linear combination of wavefunctions passing through each slit:
\Psi=R_{1}e^{i\theta_{1}}+R_{2}e^{i\theta_{2}}
and find |\Psi|^{2}

You should end up with R1^2 + R2^2 plus a cross term which exhibits the interference. Then to see why it matters if you have the same laser source or not see how coherent phases affect the cross term. For a single light source plug in \theta_{1}=\theta_{2} since they will have the same phase. If they have different phase, which would happen if you use two different sources, then their difference should vary randomly and so you should take the average value of \theta_{1}-\theta_{2} (which will give you 0 so the interference vanishes)
 
Last edited:
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top