Line of sight propagation when land is 700m above sea level

AI Thread Summary
The discussion revolves around calculating the maximum distance for a 200 MHz signal transmitted from ground level to a receiver on a multi-storey building, considering the land is 700 meters above sea level. Two equations for line of sight propagation are presented: d=√2×R×H and d=3.57√h. Initial calculations using these formulas yield a distance of 33.63 km, which is not among the provided options. Further attempts using the second formula suggest a maximum distance of 31.9 km, but there are concerns about the accuracy of the radius calculation. The thread emphasizes the importance of careful unit conversion and verification of calculations in such scenarios.
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Homework Statement



A 200 MHz signal is to be transmitted over a point-to-point wireless link. Assume the earth’s surface is flat over the entire propagation distance, and is 700 metres above sea level. The transmitter is at ground level, and the receiver is situated on top of a multi-storey office building, 80 metres from the ground. If the earth’s radius at sea level is 6,371 km, what is the maximum distance possible between transmitter and receiver (assuming no reflections off any objects)?
A.88.9km
B.31.9km
C.99.7km
D.50.5km
E.94.5km

Homework Equations



For this i got two equations
d=√2×R×H
or
d= 3.57√h


The Attempt at a Solution



Because R and the sea land is 700m above sea level.
R= 7071 km
h= 0.08km
using the first equation
d=√(2×R×H)
I get 33.63 km

but because the other one is on ground H is zero
The d=0.
making d= 33.63 isn't a option.

So i tried formula 2
I get B.31.9km.
Also when i use the first equation i used the Earth radius at sea level 6,371 km
and also get also get B.
But i have a leaving that it should be greater.

Any help appreciated
 
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Be careful when adding meters to kilometers --- check your radius calculation!
 
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