Linear Algebra and systems of linear equations problem

justin_diaz
Messages
1
Reaction score
0
The solution of the system
ax + ay - z = 1
x - ay - az = - 1
ax - y + az = 1

is (x,y,z) = (a,b,a). If a is not an integer, what is the value of a + b.

A) -3/2
B) -1
C) 0
D) 1/2
E) 1

Can anyone help I don't know how to approach thisOk then you get :

a^2 + ab -a = 1
a - ab - a^2 = -1
a^2 - b + a^2 = 1

I do not see how I can solve for a+ b to get an answer..
 
Last edited:
Physics news on Phys.org
Substitute the values for x, y, and z into your system and see what you get. Go from there.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top