Linear approximation and Multiple integral questions

fletch-j
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I am aware that for a function of two variables f(x,y) a linear approximation of a point f(x,y) close to f(x_0,y_0) can be approximated by the tangent plane approximation f(x_0+\Delta x,y_0+\Delta y)\approx f(x_0,y_0)+f_x(x_0,y_0)\Delta x+f_y(x_0,y_0)\Delta y where \Delta x=x-x_0 and \Delta y=y-y_0

So is the process the same if you have a function f(x,y) where x and y are themselves functions of more variables?
For example approximating f(x(s,t),y(s,t)) near f(x(s_0,t_0),y(s_0,t_0))

Does it scale to an arbitrary number of nested functions?

Would it be something like:

f(x(s,t),y(s,t)) \approx f(x(s_0,t_0)+x_s(s_0,t_0)\Delta s+x_t(s_0,t_0)\Delta t , y(s_0,t_0)+y_s(s_0,t_0)\Delta s+y_t(s_0,t_0)\Delta t)

or

f(x(s,t),y(s,t)) \approx f(x(s_0,t_0),y(s_0,t_0))+f_s(x(s_0,t_0),y(s_0,t_0))\Delta s + f_t(x(s_0,t_0),y(s_0,t_0))\Delta t
??Also I have this problem:

Homework Statement


Use a triple integral to find the volume of a solid cut from x=y^2 by the planes z=0 and x+z=1

I just need help setting it out, I can do the calculation myself.

9oNNV.png

The Attempt at a Solution



I had it set out as follows but I am unsure if it is correct.

\int^1_{-1} \int^1_0 \int^{1-z}_{y^2} dx dz dy

Can someone please let me know if that is incorrect and if so, what I have done wrong.

Also I was wondering, (how) could this be written as a double integral?
 
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fletch-j said:
Also I have this problem:

Homework Statement


Use a triple integral to find the volume of a solid cut from x=y^2 by the planes z=0 and x+z=1

I just need help setting it out, I can do the calculation myself.

9oNNV.png



The Attempt at a Solution



I had it set out as follows but I am unsure if it is correct.

\int^1_{-1} \int^1_0 \int^{1-z}_{y^2} dx dz dy

Can someone please let me know if that is incorrect and if so, what I have done wrong.

Also I was wondering, (how) could this be written as a double integral?

You have chosen the worst possible order of integration for this problem, which has caused you to get the middle limits incorrect. The difficulty is that if you integrate in the x direction first, you need to know the shadow of the solid in the yz plane. To get that you need to eliminate x between the cylindrical parabola and the slanted plane. The upper limit on the dz integral is not constant since it depends on y.

The easiest order would be dz dx dy. Once you work out the inner integral, what is left is how you would set the problem up as a double integral.
 
LCKurtz said:
You have chosen the worst possible order of integration for this problem, which has caused you to get the middle limits incorrect. The difficulty is that if you integrate in the x direction first, you need to know the shadow of the solid in the yz plane. To get that you need to eliminate x between the cylindrical parabola and the slanted plane. The upper limit on the dz integral is not constant since it depends on y.

The easiest order would be dz dx dy. Once you work out the inner integral, what is left is how you would set the problem up as a double integral.


Ah crap, that makes perfect sense. Thanks for being blunt.

Any ideas about about the approximation question?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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