Magnetic field on a proton due to an electron

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SUMMARY

The discussion centers on calculating the magnetic field produced by an electron in circular motion around a proton, as described in Niels Bohr's 1913 model of the hydrogen atom. The user initially calculated a magnetic field strength of 3.99T but later recognized that the correct approach involves using the Biot-Savart Law, which leads to a solution of 12.5T. The confusion arose from the interpretation of the path length, where the user initially used the circumference of the circle instead of the correct vector path length of 2r.

PREREQUISITES
  • Understanding of Niels Bohr's model of the hydrogen atom
  • Familiarity with magnetic field calculations
  • Knowledge of the Biot-Savart Law
  • Basic principles of circular motion and current
NEXT STEPS
  • Study the Biot-Savart Law in detail
  • Review the derivation of magnetic fields from moving charges
  • Explore the implications of current loops in magnetic field generation
  • Investigate the differences between Ampere's Law and the Biot-Savart Law
USEFUL FOR

Students of physics, particularly those studying electromagnetism and atomic models, as well as educators looking for practical examples of magnetic field calculations in atomic structures.

bennyq
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Homework Statement


In Niels Bohr's 1913 model of the hydrogen atom, an electron circles the proton at a distance of 5.29 E-11 m with a speed of 2.19E6 m/s. Compute the magnitude of the magnetic field this motion produces at the location of the proton.

Homework Equations


∫B.ds = μI

The Attempt at a Solution


I found the time it takes the electron to circle the proton,
then the current(I)
by dividing the Q(electron)/time

then i take ds to be 2∏r and B to be constant for the integral..

I got 3.99T, the solution gets 12.5T and uses 2r for the vector ds around the path.
Not sure how the path can be 2r?

Homework Statement


Homework Equations


The Attempt at a Solution

 
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Ampere's law doesn't seem appropriate. Consider Biot-Savart instead.
 
Ahhh i see, yes thankyou
 

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