Magnetic Flux Through Wire Loop

AI Thread Summary
The discussion centers on calculating the magnetic flux through a wire loop positioned near a straight wire carrying current. The magnetic field B at a distance r from the wire is given by B = μI/(4π), and the flux through the loop is expressed as Φ = B * da * cos(θ). Participants are attempting to combine these equations to derive the flux, particularly when the wire is in the same plane as the loop. One user provides a formula for the magnetic field in cgs units, while another seeks clarification on its derivation based on Maxwell's equations. The conversation highlights the complexity of integrating the magnetic field over the loop's area to find the total flux.
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Homework Statement


A wire loop with radius R is located a distance d from a long straight wire carrying a current I. Find the flux through the loop.

Homework Equations


B = \muI/(4\pi)
Magnetic Field above wire
\phi=B*da*cos\vartheta

The Attempt at a Solution


Somehow you have to combine the two equations to find the flux through the circular loop. Any help would be greatly appreciated as I am stumped.
 
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I don't know whether I have understood rhe problem, but I have worked out the situation in which the wire is on the same plane of the circle (in general I think that the computation is conceptually easy but hard in the practice).

In this case, the magnetic field generated by the wire at distance r is

B(r)=\frac{2I}{cr}

in cgs units.


so, if we assume that d>R>0, we have that the flux \Phi is


\Phi=\int_{d-R}^{d+R}dr\frac{2I}{cr}2\sqrt{R^2-(d-r)^2}
 
Yes you are right that the wire loop is in the same plane as the wire. Care to explain the formula you used for the magnetic field generated by the wire?
 
Yes: from the 4-th Maxwell's equation (ignoring the electric field: the problem is a magnetostatic problem):

\nabla \times \vec{B}=\frac{4\pi}{c}\vec{J}


Integrate over a surface S; transform the integral of the rotor in a line integral through one of the usual theorem (Green's theorem, maybe, but I'm not sure); moreover the integral of J gives the current and you find the relation.
 
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