Radius of Circular Path Affected by Magnetic Force: Increase or Decrease?

AI Thread Summary
When an electron moves in a magnetic field, its circular path's radius (r) is determined by the equation r = mv/Bq. As another electron moves faster in the same magnetic field, its velocity (v) increases, which affects the magnetic force (F) acting on it. Although the magnetic force increases with speed, the velocity's squared relationship in the centripetal force equation means that the increase in speed has a more significant impact, leading to an increase in the radius of the circular path. Thus, the radius of the path for the faster electron will increase compared to the slower one. The relationship between velocity and radius in a magnetic field indicates that higher speed results in a larger radius.
Gunman
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Homework Statement


An electron moves in a circular path in a vacuum under the influence of a magnetic field perpendicular to and into the paper.If there is another electron which moves with a higher speed in a circular path in the same B-field, state and explain how each of the following will be affected as compared to the first electron?
(c) The radius of the circular path


Homework Equations


F = Bqv
B = flux density
q = charge
v = velocity of the charge


The Attempt at a Solution



F(m) = Bqv
Since F(m) causes the centripetal acceleration of electron
F(m) = Bqv = mv^2/r
r = mv/Bq
Therefore it can be concluded that r increases as v increases?

But how can this be case as,
F(m) = Bqv, and F(m) increases as velocity of the charge increases
If F(m) increases, r would decrease as it is inversely proportional to F
in the equation F(m) = mv^2/r.

So would r increase or decrease if a faster electron moves in a circular path in a vacuum under the influence of a magnetic field perpendicular to and into the paper.
 

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Gunman said:

Homework Statement


An electron moves in a circular path in a vacuum under the influence of a magnetic field perpendicular to and into the paper.If there is another electron which moves with a higher speed in a circular path in the same B-field, state and explain how each of the following will be affected as compared to the first electron?
(c) The radius of the circular path


Homework Equations


F = Bqv
B = flux density
q = charge
v = velocity of the charge


The Attempt at a Solution



F(m) = Bqv
Since F(m) causes the centripetal acceleration of electron
F(m) = Bqv = mv^2/r
r = mv/Bq
Therefore it can be concluded that r increases as v increases?

But how can this be case as,
F(m) = Bqv, and F(m) increases as velocity of the charge increases
If F(m) increases, r would decrease as it is inversely proportional to F
in the equation F(m) = mv^2/r.

So would r increase or decrease if a faster electron moves in a circular path in a vacuum under the influence of a magnetic field perpendicular to and into the paper.
You have clearly put a lot of thought into this question, perhaps a little too much :wink:. Consider your final equation,

F = \frac{mv^2}{r}

And your final comment,
Gunman said:
If F(m) increases, r would decrease as it is inversely proportional to F
You are correct that the magnetic force increases, but you forget that the speed v has also increased. Notice that the speed is raised to the second power and therefore will have a much greater effect on the magnetic force that the radius since the radius is only raised to the fist power.
 
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