Magnetic Forces: Deriving Equation to Balance Rider Weight

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SUMMARY

The discussion centers on deriving the equation for balancing the weight of a rider using magnetic forces between current-carrying wires. The magnetic force of mutual repulsion is expressed as F = μ₀ I₁ I₂ L / (2πr), which must counterbalance the rider's weight (mg). The contribution from the Earth's magnetic field is also considered, leading to the conclusion that the effective force can be simplified by substituting I² with I₁I₂, allowing for the cancellation of external magnetic influences. The final equation for plotting is I₁I₂ = (g2πr / μ₀L)m.

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  • Familiarity with the concept of mutual induction
  • Knowledge of basic algebra and rearranging equations
  • Basic principles of electromagnetism, including Earth's magnetic field effects
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BOAS
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Hello,

i'm working through some prep required for my lab course and having some trouble understanding an equation. We're asked to show it's derivation and I think I've done this but the script itself is a bit ambigous about how to get there.

Homework Statement



The magnetic force of mutual repulsion between the wires is [itex]F = \frac{\mu_{0} I^{2} L}{2 \pi r}[/itex]

Ideally this force should balance the weight of the rider, however there may also be a contribution from the Earth's magnetic field, which will add a force [itex]B_{e} IL[/itex]

By replacing [itex]I^{2}[/itex] with [itex]I_{1}I_{2}[/itex] the effect of the external fields should cancel.

Homework Equations





The Attempt at a Solution



Depending on the direction of the current, the Earth's magnetic field is either contributing to or opposing the force due to the magnetic field of the wire, so

[itex]F_{1} = \frac{\mu_{0} I_{1}I_{2} L}{2 \pi r} + B_{e} IL[/itex]

[itex]F_{2} = \frac{\mu_{0} I_{1}I_{2} L}{2 \pi r} - B_{e} IL[/itex]

[itex]F_{1} + F_{2} = \frac{\mu_{0} I_{1}I_{2} L + \mu_{0} I_{1}I_{2}L}{2 \pi r}[/itex] (Earth's magnetic field cancels)

[itex]2F = \frac{2(\mu_{0} I_{1}I_{2} L) }{2 \pi r}[/itex]

[itex]F = \frac{\mu_{0} I_{1}I_{2} L}{2 \pi r}[/itex] this is the equation I wanted to reach. Are my steps to get here ok? I don't really know how to put into words the importance of substituting I^2 for I1I2...

Since this force should balance the weight of the rider we can say;

[itex]mg = \frac{\mu_{0} I_{1}I_{2} L}{2 \pi r}[/itex] and rearrange to get

[itex]I_{1}I_{2} = (\frac{g2 \pi r}{\mu_{0} L}m[/itex] Which is what I want to plot a graph of)

Apologies if this is a bit of a vague post, but I don't have much practice of lab work and I don't know if my steps count as showing why the magnetic field of the Earth cancels due to the substitution of I^2 that I made. I do include a few more steps in the algebra in my book, showing explicitly the force due to the Earth's magnetic field cancelling etc.

Thanks,

BOAS
 
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You're not getting much quick help here. Could it be the problem formulation is somewhat unclear to others ? They may know about forces between current carrying wires, but who is riding them ?
You are to do some experiment, measure something and plot the results in a smart way, right ?
 

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