Magnitude of an Electric Field in a Cylinder

AI Thread Summary
The problem involves calculating the electric field magnitude at a radial distance of 2.30 mm from the center of a thin metal wire within a cylindrical copper shell. Both the wire and shell have equal and opposite linear charge densities of 6.35 x 10^-9 C/cm. To find the electric field, Gauss's law is applied, using the equation EA = E*2*π*r*L = (λ*L)/ε0. The key is to determine the enclosed charge and apply the appropriate values to solve for E. The solution emphasizes the uniform distribution of charge and the geometry of the system.
freddy13
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Homework Statement


A thin, cylindrical copper shell of diameter ds = 2 cm has along its axis a thin metal wire of diameter dw = 7.50 x 10-03 cm. (as shown in the diagram below.) The wire and the shell carry equal and opposite charges of 6.35 x 10-09 C/cm, distributed uniformly. What is the magnitude of the electric field at a point r = 2.30 mm, where r is measured radially from the center of the inner wire?


Homework Equations



I think EA = E*2*∏*r*L = (λ*L)/ε0
 
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Use Gauss law here. Flux = Q(in)
 
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