Magnitude of an Electric Field in a Cylinder

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SUMMARY

The discussion focuses on calculating the magnitude of the electric field generated by a thin cylindrical copper shell and a central wire, both carrying equal and opposite linear charge densities of 6.35 x 10-9 C/cm. The relevant formula derived from Gauss's law is EA = E*2*∏*r*L = (λ*L)/ε0, where E is the electric field, r is the radial distance (2.30 mm), and λ is the linear charge density. The analysis confirms that the electric field can be determined using these parameters and the principles of electrostatics.

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  • Understanding of Gauss's law in electrostatics
  • Familiarity with electric field calculations
  • Knowledge of linear charge density concepts
  • Basic principles of cylindrical symmetry in electric fields
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  • Study the application of Gauss's law in various geometries
  • Learn about electric field calculations for cylindrical conductors
  • Explore the concept of linear charge density in electrostatics
  • Investigate the effects of dielectric materials on electric fields
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Students in physics, electrical engineering majors, and anyone interested in electrostatics and electric field calculations in cylindrical geometries.

freddy13
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Homework Statement


A thin, cylindrical copper shell of diameter ds = 2 cm has along its axis a thin metal wire of diameter dw = 7.50 x 10-03 cm. (as shown in the diagram below.) The wire and the shell carry equal and opposite charges of 6.35 x 10-09 C/cm, distributed uniformly. What is the magnitude of the electric field at a point r = 2.30 mm, where r is measured radially from the center of the inner wire?


Homework Equations



I think EA = E*2*∏*r*L = (λ*L)/ε0
 
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Use Gauss law here. Flux = Q(in)
 

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