(adsbygoogle = window.adsbygoogle || []).push({}); maple issue -- inverse laplace transform equation from a basic series RLC circuit

Pretty simple for some of you I know, but I have a laplace transform equation from a basic series RLC circuit

((sV-v(0))/L+si(0))/(s^2+sR/L+1/LC) = I(s)

I want to take the inverse laplace of it, I am given all initial conditions, and constants for R,L, and C.

I've done laplace but cannot figure out how to take the inverse of this one, and cannot figure how to check it with maple..

Any help appreciated.

EDIT: initial conditions are L = 10H, v = 10v C = 1000uF i(0) = 1A R = 100ohms

Can I just fill in values at this point and attain 2s-.5/s^2+10s+100 and simplify this and bring it back to the time domain?

Sorry, im asked for the current response in the time domain.. So I think this is the right approach... maybe I have made a mistake.

Any help with the maple would still be appreciated greatly. I am new to the program.

I get 2e^-5tcos(sqrt75)t - (21/2(sqrt75))e^-5tsin(sqrt75)t

I was expecting a cleaner result....

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# Maple issue - inverse laplace transform equation from a basic series RLC circuit

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