Mass Needed to Keep Rod Spinning at 1200RPM

AI Thread Summary
To maintain a rod spinning at 1200 RPM with three metal blocks, the required mass of the blocks is not directly related to the 15 HP needed to overcome friction and keep the generator running. The power consumed is primarily to counteract losses due to friction, not to drive the system's inertia. The masses can act as a flywheel if the torque input is pulsed, helping to smooth energy transfer. However, without additional energy input, the system cannot create free energy, as energy conservation principles apply. Understanding the relationship between torque, power, and friction is crucial for this setup.
Giesick
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Homework Statement



I have three metal blocks evenly spaced in a 0.3m circle that attach to a rod in the center of the circle. The rod requires 15HP to keep rotating at 1200RPM. What would the mass of the three blocks spinning at 1200RPMs need to be in order to produce 15HP? My physics class hasn't got to anything that would help me figure this out, so I don't even know where to start. I need this for a something I'm trying to build not for school.
Thanks

Homework Equations





The Attempt at a Solution

 
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Since power is related to torque and rotation rate, you can find the torque required to keep the rod spinning. Generally, the equation used to relate torque to rotation is:

T=I*\alpha

What you're asking is how the geometry and mass of these blocks affects the inertia of the system (I, in the above equation). However, in your case \alpha is zero because you're at a constant speed, which means you don't need any torque (or power) to maintain it. The equation you're looking for probably looks something like:

T=I*\alpha+b*\omega

or

T=I*\alpha+c

or a combination/variation of the two of them, where b and c are related to the viscous damping coulomb friction in the system.

So basically what I am trying to say, is that you don't have enough information. If you're using 15 HP to maintain, then you have some kind of friction in your system, and this power is being used to overcome those losses, not to drive your system's inertia. In fact, those masses should be independent of the power consumed at a constant speed.

I feel like I did a lousy job explaining this... was I clear enough?

-Kerry
 
I just answered this same post (by you...) in another forum. Isn't that a no-no?
 
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I merged the two threads. Yes, multiple posting of threads is not allowed here on the PF.
 
Sorry about that, I didn't know which place to post it so I did it in both. What I'm trying to figure out is I have a generator and they told me it takes 15HP to keep the generator turning while it is under rated load. I just wanted to know if the masses are large enough and spinning fast enough, would it keep the generator spinning and still producing energy. So what other info would I need, or is it even possible?
 
If you have system that is creating energy, and it is not loosing any energy (it's not slowing down) and there's no energy being put into the system (no fuel and combustion, for example), then you're creating "free" energy. You could solve the world's energy problems...

Unfortunately, this is not possible. Energy must be conserved (Google 'First Law of Thermodynamics' or 'Law of Conservation of Energy'). If energy is leaving your system (via electrical current, in your case), then the system will loose energy (slow down) or energy must be put back into the system.

-Kerry
 
Giesick said:
Sorry about that, I didn't know which place to post it so I did it in both. What I'm trying to figure out is I have a generator and they told me it takes 15HP to keep the generator turning while it is under rated load. I just wanted to know if the masses are large enough and spinning fast enough, would it keep the generator spinning and still producing energy. So what other info would I need, or is it even possible?

The masses have nothing to do with the question, unless the torque input power is pulsed. Then the masses can act as a flywheel to smooth the energy transfer. The torque input on the shaft of your generator is what results in the electrical power output.
 
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