Material Breakdown Due to Electron Beam

ajhunte
Messages
12
Reaction score
0
The problem asks me to determine the rate of breakdown due to firing 120 kev Electrons at Titanium of arbitrary thickness. I could solve this problem if I knew The average energy deposited per electron, or the Energy efficiency of the entire beam through the titanium.

Given:
Electron Flux (Current)=8.75e16 Electrons per second
Energy of Electrons= 120 keV per Electron
Density of Titanium= 4.506 g per cm^3
Thickness of Titanium= .0254 cm
Surface area of Titanium= 100 cm^2

Is there a formula that accurately describes the attenuation coefficient of electrons (or beta particles) based on the Z (# of protons) of the absorber. I am interested in the average energy deposited per electron or average energy deposited per second.
 
Physics news on Phys.org
You may find this useful:

http://physics.nist.gov/PhysRefData/Star/Text/ESTAR.html"
 
Last edited by a moderator:
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top