Max Acceleration from Friction w/ Coeff 0.95: 9.3 m/s2

AI Thread Summary
The greatest acceleration a runner can achieve with a coefficient of static friction of 0.95 is calculated to be 9.3 m/s². This is derived from the equation a_max = u_s * g, where u_s is the coefficient of static friction and g is the acceleration due to gravity. The friction force acts in the direction of acceleration, which is to the right on the positive x-axis. When a runner pushes backward, the friction force must counteract this to allow forward acceleration. Understanding the role of friction is crucial, as it enables acceleration rather than deceleration.
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Homework Statement


What is the greatest acceleration that can be generated by a runner if the coefficient of static friction between shoes and road is 0.95?


Homework Equations


Fnet = ma
Force of static friction: usN
Weight= mg



The Attempt at a Solution


FBD: Positive x-axis is to the right. Positive y-axis is to the top. Normal force pointing up, equal in magnitude to weight pointing down. Friction must point in the positive x direction.

f = max
ax = usg
amax = (0.95*9.81)
= 9.3 m/s2

I just have one question. Does the friction force point to the right, in the direction of the positive x axis? Thanks!
 
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To answer your one question yourself you can imagine trying to accelerate on an (almost) friction-free surface, such as ice.
 
So the friction force would point to the right? Due to Fnet = ma, the acceleration and net force should be in the same direction. The only way this is possible is the friction force pointing to the right.
 
Yes, if the runner is trying to accelerate in the positive x direction (I didn't find that all too clearly in the story...). Runner pushes backward, exercises a force in the -x direction. No slipping means there must be a force in the +x direction to offset it: the friction force.

Compare with car braking: friction slows it down. Accelerating: friction allows it to accelerate.
 
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