Max Speed for 10 m Radius Spinning Drum Ride

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Homework Statement


If a spinning drum ride cannot exceed a 10 m radius, and the riders are not to
experience an acceleration greater than 2g, what is the maximum speed at
which the drum can spin?


Homework Equations


No Idea


The Attempt at a Solution


I tried using (theta) = tan-1 of (rg/v2)
v2 = (tan(theta))/(rg)
v = (root) of (tan(theta))/(rg)
 
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Hi Alcape! :smile:

(have a theta: θ :wink:)
Alcape said:
If a spinning drum ride cannot exceed a 10 m radius, and the riders are not to
experience an acceleration greater than 2g, what is the maximum speed at
which the drum can spin?

I tried using (theta) = tan-1 of (rg/v2)
v2 = (tan(theta))/(rg)
v = (root) of (tan(theta))/(rg)

What's θ? :confused: You can assume that the drum's wall are vertical. :wink:

Now use the standard formula for centripetal acceleration :smile:
 
If the walls are vertical then it doesn't work as it's at 90 degrees and tangent of 90 degrees then it comes out to be a mathematical error
 
ah … you obviously haven't seen one of these at a fairground. :biggrin:

Yes, if the walls are smooth, it can't be done, but you can assume the walls are rough, so that friction will keep you up (or even that there's a ledge to stand on :wink:).
 
I now have the answer if you use the formula for acceleration:a=v2/r
and transpose it so that it becomes: v2 = a*r and therefore becomes:
v = √(a*r) and it comes out to be 4.47...
 
Hi Alcape! :smile:

(just got up :zzz: …)
Alcape said:
I now have the answer if you use the formula for acceleration:a=v2/r
and transpose it so that it becomes: v2 = a*r and therefore becomes:
v = √(a*r) and it comes out to be 4.47...

what about g ? :redface:

(and are you sure the question isn't asking for the angular speed?)
 
Yes I'm sure as this is question a and b asks for the angle
 
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