Max Vertical Reach at Back Wall: Solving Projectile Problem

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The discussion focuses on solving a projectile problem to determine the maximum vertical reach at a back wall, incorporating an initial standing reach. Key equations for projectile motion are provided, including the kinematic equations for distance and velocity. The user has launched a ball at 20 m/s at a 60-degree angle but seeks clarification on the specifics of the problem, including the wall's location. Participants encourage the user to share their work and identify where they are experiencing difficulties. The conversation emphasizes the importance of diagrams and qualitative analysis of jumping differences between terrestrial and lunar environments.
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Homework Statement


Finding the maximum vertical reach at the back wall.
This should be viewed as a peak height projectile problem (added to an
initial standing reach). Are diagrams
included to show the meaning of each variable? Are reasonable and unique
values used? Is the maximum vertical reach found? Is there a qualitative
analysis about the many dramatic differences between Terrestrial and Lunar jumping?

Homework Equations


d= vit+1/2at^2
vf^2=vi^2+2ad

The Attempt at a Solution


ball launched at 20 m/s. 60 degree angle.
 
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Welcome to PF!

Hi xL0VEN0TE! Welcome to PF! :wink:

What exactly is your question (and where is the wall)? :confused:

Anyway, show us what you've done, and where you're stuck, and then we'll know how to help. :smile:
 
Thanks. Sorry, I'm still kind of new to this website.
I just need to create a projectile problem with that info given.
 
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