Is My Calculation of Maximum Power Correct in This Circuit Analysis?

AI Thread Summary
The discussion revolves around calculating maximum power in a circuit analysis, focusing on finding the Thevenin equivalent voltage (Vth) and resistance (Rth). The initial calculations for Rth were confirmed as correct at 2/7, while the value for Vth was debated, with one participant initially calculating it as 15V but later correcting it to approximately 8.5V. The equations used for nodal and mesh analysis were discussed, with some adjustments made to ensure accuracy. Ultimately, the maximum power calculation, Pmax, was derived from the corrected values, leading to a consensus on the methodology used. The thread emphasizes the importance of verifying calculations in circuit analysis.
salman213
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1. http://img503.imageshack.us/img503/1480/21144697lh1.jpg [/URL]

3.
Pmax = Vth^2/4Rth

so I am guessing i treat R as the Rth and find Rth.

to find Rth i must turn off all independent sources. Since the dependent source exists i added a one voltage source at the Rth terminals and put a current i which i will find. then i can use v=i*Rth to solve for Rth.

my mesh analysis equations:
Vx + 1 =0
-1 + i2 + 2Vx=0

therefore i2 = 3

2i3 + 1 =0
i3 =-1/2



i3 + i1 = i2

therefore

i1 = 1/2 + 3

i1 = 7/2


Rth = (1)/(7/2) = 2/7


now to find Vth

I used nodal analysis and mesh analysis both

1) (12-Vth)/2 = (Vth-2Vx)/1
2) -12 + Vx + Vth=0

Solving I found Vth = 15 V


Pmax = Vth^2/4Rth = (15)^2 / (4(2/7)) = 196.874 W



CAN SOMEONE PLEASE CHECK THAT!


thank you!





 
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I didn't get Vth to be 15V. I got 8\frac{4}{7}. But I got the same value for Rth.
 
are my equations right?

for solving Vth?

1) (12-Vth)/2 = (Vth-2Vx)/1
2) -12 + Vx + Vth=0
 
1) (12-Vth)/2 = (Vth-2Vx)/1
2) -12 + Vx + Vth=0

vx= 12 - vth

(12-Vth)/2 = (Vth-2( 12 - vth))/1

12-Vth = 2Vth-48+4vth

12+48=vth+2vth+4vth
60=7vth

okk ur right its 8.5ishok kool
 

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