MCQ: Law of independent assortment

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Discussion Overview

The discussion revolves around the Law of Independent Assortment in the context of a multiple-choice question (MCQ) related to the segregation of homologous chromosomes during meiosis. Participants explore the implications of this law on the probabilities of different chromosome combinations in gametes.

Discussion Character

  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant suggests that the answer to the MCQ is (d) based on the law of independent assortment allowing for any combination of chromosomes during segregation.
  • Another participant questions how two options can occur each with 100% probability, indicating confusion about the nature of the combinations.
  • Some participants propose that the combinations are not generated simultaneously, implying that only one combination can occur at a time.
  • There is a suggestion to consider the expected distribution of gametes showing each combination, raising questions about the interpretation of ratios in this context.
  • One participant expresses uncertainty about the relevance of a 1:1 ratio to independent assortment, seeking clarification on its implications.
  • Another participant concludes that the chances of obtaining each combination is 50%, affirming the correctness of answer (a) based on this reasoning.

Areas of Agreement / Disagreement

Participants express differing views on the interpretation of the probabilities associated with the combinations of chromosomes, leading to an unresolved discussion about the correct answer to the MCQ and the implications of the law of independent assortment.

Contextual Notes

Participants reference the stages of meiosis and the expected outcomes in terms of gamete combinations, but there is no consensus on how these relate to the specific question posed in the MCQ.

TytoAlba95
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Homework Statement
Please find the attachment below
Relevant Equations
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245311


Answer: (a)

Attempt:
In Metaphase I, homologous chromosomes separate. Out of the four options, dig (a) and (d) have correct representation of separating homologous chromosomes.

Now, according to the law of independent assortment, during segregation the chromosomes can group in any combination. So I think (d) should be the correct option i.e. either of the combination can occur.

The answer provided is (a) , am I missing on something.
 
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How can two options occur each with 100% probability?
 
Ygggdrasil said:
How can two options occur each with 100% probability?
I think, they are not generated at the same time, it either the first or the second combination.
 
Perhaps think of it this way: if you have 100 gametes, how many gametes do you expect to show the first combination and how many gametes do you expect to show the second combination?
 
Ygggdrasil said:
Perhaps think of it this way: if you have 100 gametes, how many gametes do you expect to show the first combination and how many gametes do you expect to show the second combination?

Sorry, I still can't get it. Does 1:1 ratio got something to do with independent assortment?
 
Ygggdrasil said:
Perhaps think of it this way: if you have 100 gametes, how many gametes do you expect to show the first combination and how many gametes do you expect to show the second combination?
Hope you don't mind discussing this question after so many months of dormancy.
The 1st combination can be anything, say x% , then the second combination will be (100- x)%.

So 50% : 50% is an arbitrary percentage they have assigned to the two combinations? Still (a) is the correct answer based on this logic?
 
SanjuktaGhosh said:
Hope you don't mind discussing this question after so many months of dormancy.
The 1st combination can be anything, say x% , then the second combination will be (100- x)%.

So 50% : 50% is an arbitrary percentage they have assigned to the two combinations? Still (a) is the correct answer based on this logic?

Based on the Law of Independent Assortment (which can be derived from understanding what happens at the various stages of meiosis), you would expect 50% of cells to show the arrangement on the left of (a) and 50% of the cells to show the arrangment on the right (a).
 
I completely get you, the chances of getting each combination is 1/2 or 50%. Thank you. :)
 

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