Mechanics, rewrite and solve equation, change of variables.

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Homework Help Overview

The discussion revolves around rewriting a given equation from mechanics, specifically focusing on the relationship between acceleration, velocity, and position. The original equation involves terms related to gravitational force and drag, and participants are tasked with expressing velocity as a function of position.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to rewrite the equation as a differential equation for velocity, expressing concerns about the correctness of their formulation. They explore integrating the equation but express confusion regarding the terms involved, particularly the squared velocity. Other participants suggest using the chain rule to relate derivatives with respect to position instead of time.

Discussion Status

Participants are actively engaging in clarifying the formulation of the differential equation. Some guidance has been provided regarding the use of the chain rule and the correct expression for velocity in terms of position. There is a recognition of the need to separate variables for further analysis, but no consensus on a complete solution has been reached.

Contextual Notes

Participants are navigating the complexities of transforming the equation while adhering to the constraints of the problem, including the requirement to express velocity as a function of position rather than time.

fed_ex
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Equation found in previous question is #: x''=gsin(a)-b(v^2)
1. Rewrite the equation # as a differential equation for v as a function of x.
2. Solve the equation to find v as a function of x.

Relevant equations: v=x'=dx/dt, x''=v'=a=dv/dt
Attempt at 1: Using the relevant equations you can rewrite # as
*: dv/dt=gsin(a) - b((x')^2)
Which i am scepticle of being correct due to my inability to solve it in the 2nd part.
Attempts at 2:Tried integrating but the whole((x')^2) confused me, i was thinking of making that (dx/dt)*(dx/dt) but got stuck again.
Tried to rewrite * but i was expecting a first order LINEAR equation, so that i could use the integrating factor method, so alas that also didn't work.


Any help would be appreciated, thankyou.
 
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hi fed_ex! welcome to pf! :smile:

(try using the X2 button just above the Reply box :wink:)
fed_ex said:
dv/dt=gsin(a) - b((x')^2)

correct, but you've gone a bit too far …

try dv/dt=gsin(a) - b(v2) :wink:
 
You are asked to find a differential equation for v as a function of x so you want derivatives with respect to x, not t.
By the chain rule, x''= dv/dt= (dv/dx)(dx/dt)= v (dv/dx).

Replacing x'' in the equation by v (dv/dx) gives the equation you want.
 
Ah yes! Then separate and enjoy tasty solution.
Thanks!
 

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