Mixing two liquids with equal mass, find pressure

AI Thread Summary
When mixing two liquids of equal mass, one with density ρ and the other with density 2ρ, the total volume remains unchanged. The calculations show that the total volume V is equal to 3m/2ρ, leading to a new density of the mixture, ρ' = 2m/V. The final density of the mixture is determined to be 3/2ρ. The solution process involved using the relationship between mass, volume, and density, ultimately confirming the correct answer. The discussion highlights the simplicity of the problem despite initial confusion.
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Homework Statement


A mass of a liquid of density ρ is thoroughly mixed with an equal mass of another liquid of density 2ρ. No change of the total volume occurs.

Homework Equations


The Attempt at a Solution


i tried to use ρ=\frac{m}{v}
then v=\frac{m}{\rho}
therefore v1+v2=V
\frac{m}{\rho}+\frac{m}{2\rho}=v
\frac{3m}{2\rho}=V
\frac{3m}{2V}=\rho1
\rho1 \ \rho
in the end i get \rho1 = \frac{3}{2}\rho

but i was wrong couldn't find out the reason ><
 
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Total volume V = 3m/2ρ

Total mass = 2m

So new density ρ' = 2m/V = ...?
 


oh no
!@#$%^&*()
=.=
cant think that this could be that simple ><
but anyway its the right answer
ths for solving it for me
 
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