Calculate the mass (in grams) of KHP required to react completely with the NaOH in 35 mL of 0.100M NaOH.
KHP = KHC8H4O4(aq)
molar mass of "KHP"= 204.2 g/mol
This is a double replacement reaction of the acid-base neutralization type. In other words the K will be replaced with Na and the product will have H2O in the mix.
The Attempt at a Solution
It wants KHP in grams.
g/m * m/L*
See this is where I get lost. I'm sure its something simple. Also m/l = M. Just to make sure, if I have the volume (L) and the Molarity (M) to get the moles, the only thing i have to do is multiple the volume by the molarity?