Calculate the moment of inertia of a uniform solid cone

AI Thread Summary
To calculate the moment of inertia of a uniform solid cone about an axis through its center, the relevant equation is I = ∫r²dm. The discussion emphasizes the need to incorporate the density function to convert dm into a suitable differential element for integration. The expected result is 3/10 MR², but participants express uncertainty about the integration process and the appropriate setup for the triple integral. Suggestions include reviewing examples from external resources and sharing progress for further assistance. Understanding the integration method is crucial for solving moment of inertia problems effectively.
ehilge
Messages
160
Reaction score
0

Homework Statement



Calculate the moment of inertia of a uniform solid cone about an axis through its center. The cone has mass M and altitude h. The radius of its circular base is R. (see attached photo)



Homework Equations


I know I need to somehow use the equation I=\intr<sup>2</sup>dm
also, I have an equation from my proffessor, dm=\rhodv I'm not sure if I need this though since its unifrom density so it doesn't seem like \rho should matter.

The Attempt at a Solution


I don't have a solution right now. I know the answer is 3/10 MR2 but I don't know how to het there. From class, since we did some examples, I think I need an equation that has a triple integral in it but I don't know what to integrate and to where.

Thanks for your help. Also, if you have any general suggestions on how to complete moment of inertia problems like this that would be great. I know we're going to be doing a lot of them.

Thanks again!
 

Attachments

  • cone.jpg
    cone.jpg
    5.2 KB · Views: 1,314
Physics news on Phys.org
Hi ehilge,


ehilge said:

Homework Statement



Calculate the moment of inertia of a uniform solid cone about an axis through its center. The cone has mass M and altitude h. The radius of its circular base is R. (see attached photo)



Homework Equations


I know I need to somehow use the equation I=\intr<sup>2</sup>dm

To put this in tex, don't use the [noparse][/noparse]. Use the caret ^, and put a space before the r, like this:

[noparse]\int r^2 dm[/noparse]

which gives:

\int r^2 dm

also, I have an equation from my proffessor, dm=\rhodv I'm not sure if I need this though since its unifrom density so it doesn't seem like \rho should matter.

Yes, you'll need some form of the density. The integral has a dm in it, and you need to use the density function to change that to a dx, dA, dV, etc. (depending on the type of shape) so that you can perform the integration.

The Attempt at a Solution


I don't have a solution right now. I know the answer is 3/10 MR2 but I don't know how to het there. From class, since we did some examples, I think I need an equation that has a triple integral in it but I don't know what to integrate and to where.

Thanks for your help. Also, if you have any general suggestions on how to complete moment of inertia problems like this that would be great. I know we're going to be doing a lot of them.

Thanks again!

If you look here

http://hyperphysics.phy-astr.gsu.edu/hbase/mi.html#mig

and scroll to near the bottom you will see links to three examples. Does that help?

If you get stuck on the cone calculation, post your work and where you are getting stuck and maybe someone can help.
 
I was able to get the problem figured out. Thanks for your suggestions and also with the help with formatting.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top