Motion 2 problems - Tossing hay bales and baseballs

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The discussion focuses on solving two motion problems involving projectile motion: one about a hay-baling machine launching bales and another about a baseball hit into the air. For the hay bale, the key is to determine the launch speed needed to reach a height of 2.0 m while landing 4.7 m away, utilizing vertical motion equations and gravitational acceleration. The baseball problem requires finding the launch angle after it remains airborne for 6.3 seconds and travels 83 m horizontally, necessitating the calculation of vertical and horizontal velocity components. Participants emphasize the importance of understanding the relationships between vertical and horizontal motions and using the correct equations to solve for unknowns. Clear step-by-step problem-solving is encouraged to avoid confusion.
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Motion 2 problems -- Tossing hay bales and baseballs

Homework Statement


1. A hay-baling machine throws each finished bundle of hay 2.0 m up in the air so it can land on a trailer waiting 4.7 m behind the machine.

(a) What must be the speed with which the bundles are launched?

2. A baseball is popped up, remaining aloft for 6.3 s before being caught at a horizontal distance of 83 m from the starting point. What was the launch angle?





Homework Equations


1. x = 1/2at^2 +vot +x0
x-xo = d

2. vx = cos*vo
vy = sin*vo


The Attempt at a Solution


1. I used the distance and plugged it into the first equation but it is the wrong answer I believe.
2. I know that in the end I have to divdide vy by vx and take the arctan of that but I do not understand how to find vy and vx. Can someone explain to me step by and step and what that means?
 
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blackraven said:

The Attempt at a Solution


1. I used the distance and plugged it into the first equation but it is the wrong answer I believe.
2. I know that in the end I have to divdide vy by vx and take the arctan of that but I do not understand how to find vy and vx. Can someone explain to me step by and step and what that means?

Let's first talk about the vertical motion. At the maximum height, velocity is zero. Initially, the vertical velocity is vsinθ (a component of the initial velocity making an angle θ with the ground). You have initial velocity, final velocity, displacement and the acceleration.
Can you form an equation now?
 


This is going to sound like weird advice, but you're not thinking about the problem right. Don't think "I know that in the end I have to..." Just work through it.

Your equations are sound. Let's start with this: you know the maximum height right? What can you find with that if you know the acceleration of gravity?
 


blackraven said:
1



Homework Equations


1. x = 1/2at^2 +vot +x0
x-xo = d

2. vx = cos*vo
vy = sin*vo



ISEE Method

1. Identify
a) Only one object - the hay bale
b) The object doing 2 works. Going in horizontal and verical motion.

2. Select
y=y0+vy0ty+(1/2)ayty2
x=x0+vx0tx+(1/2)axtx2

Since it involves only one object,
ty=tx

3. Execute
4. Evaluate
 
Last edited:
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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